Question #90097
A disc of moment of inertia of a body about s given axis 15kgm^2 rotates constantly about the centre with an angular velocity of 20rads^-1. find its rotational energy and its angular momentum about the centre
1
Expert's answer
2019-05-24T10:39:58-0400

Denote II - moment of inertia and ω\omega -angular velocity.

Then rotational energy is


E=Iω22=15×2022=3000JE=\frac{I\omega^2}{2}=\frac{15\times20^2}{2}=3000 J

and angular momentum is


L=Iω=20×15=300kg×msL=I\omega=20\times 15=300 \frac{kg\times m}{s}


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