Let the copper wire be 1 with Young's modulus 110 GPa, and the steel wire be 2 with Young's modulus 200 GPa. Their own elongations thus:
"x_2=\\sigma\\frac{L_2}{E_2}."
On the other hand,
"x_1+x_2=l."Dividing the first two equations one by another, we get an equation for the system of equations with the third one:
solve:
"x_1=l-x_2=4.5\\cdot10^{-3}\\text{ m}."
Comments
Leave a comment