Question

What velocity should a clock be moved related to the observer so that it may seems to lose 1 minute per day

Answer 1

Time in relativistic physics is determined as

$$T=\frac{T_0}{\sqrt{1-\frac{v^2}{c^2}}}$$

So, if The interval for observer

$$T_0=86400 (s)$$

then interval for clock be moved related to the observer

$$T=86460 (s)$$

Velocity is

$$v=c\sqrt{1-(\frac{T_0}{T})^2}$$

calculating

$$v=3\cdot 10^8\cdot \sqrt{1-(\frac{86400}{86460})^2}=11.2 (Mm\cdot s^{-1})$$