Question #88928
What is the total energy of an electron when its momentum is 10 times its it is multiplied by the light velocity (rest mass of electron equals to 9×10^-31 kg)
1
Expert's answer
2019-05-07T09:56:30-0400

The total energy of an electron depends on its rest energy and kinetic energy:


E=(m0c2)2+(pc)2=(m0c2)2+([10m0c]c)2,E=\sqrt{(m_0c^2)^2+(pc)^2}=\sqrt{(m_0c^2)^2+([10m_0c]c)^2},

E=(91031(3108)2)2+([10910313108]3108)2=E=\sqrt{(9\cdot10^{-31}(3\cdot10^8)^2)^2+([10\cdot9\cdot10^{-31}\cdot3\cdot10^8]3\cdot10^8)^2}=

=8.141013 J.=8.14\cdot10^{-13}\text{ J}.


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