Answer to Question #88926 in Mechanics | Relativity for Sridhar

Mechanics | Relativity

Question #88926

Two particle comes towards each other with a speed 0.8c with respect to the laboratory their relative speed is

Expert's answer

in this case, the relative speed

"u=\\frac{2v}{1+(\\frac{v}{c})^{2}}=\\frac{1.6c}{1+0.64} = 0.98c"

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