Question

An electron with initial velocity v0 = 1.95 × 105 m/s enters a region 1.0 cm long where it is electrically accelerated (see the figure). It emerges with velocity v = 5.08 × 106 m/s. What is its acceleration, assumed constant? (Such a process occurs in conventional television sets.)

Answer 1

The distance traveled by electron

$$d=\frac{v_f^2-v_i^2}{2a}$$

So, the acceleration

$$a=\frac{v_f^2-v_i^2}{2d}$$

$$=\frac{(5.08\times 10^6)^2-(1.95\times 10^5)^2}{2\times 0.01}$$

$$=1.29\times 10^{15}\:\rm{m/s^2}$$