Answer to Question #88213 in Mechanics | Relativity for Amoo Emmanuel

Question

Niagara Falls are 50n high. Calculate the potential energy of 0.1cubic meter of water at the top relative to the bottom. Density of water is 1000kgm^-3. g=10m/s^2

Answer 1

The potential energy

$$PE=mgh=\rho V g h$$

$$=1000\:\rm{kg /m^3}\times 0.1\;\rm{m^3}\times 10\;\rm{m/s^2}\times 50\;\rm{m}=50 000 \:\rm{J}$$ $$=50\:\rm{kJ}$$