Answer to Question #88213 in Mechanics | Relativity for Amoo Emmanuel

Question #88213
Niagara Falls are 50n high. Calculate the potential energy of 0.1cubic meter of water at the top relative to the bottom. Density of water is 1000kgm^-3. g=10m/s^2
1
Expert's answer
2019-04-18T09:57:44-0400

The potential energy

PE=mgh=ρVghPE=mgh=\rho V g h

=1000kg/m3×0.1  m3×10  m/s2×50  m=50000J=1000\:\rm{kg /m^3}\times 0.1\;\rm{m^3}\times 10\;\rm{m/s^2}\times 50\;\rm{m}=50 000 \:\rm{J}=50kJ=50\:\rm{kJ}


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