Question #88186
A gun of mass 10kg released a bullet of mass 20gm at a speed of 100m/s. Find the gun's speed of recoil
1
Expert's answer
2019-04-17T11:14:39-0400

Following momentum conservation law,


Mv=muMv = mu

v=muM=2010010103=0.2m/sv = \frac{mu}{M} = \frac{20 \cdot 100}{10\cdot 10^3}=0.2 \, \text{m/s}


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Comments

Maruf-Hassan Zaynab Abake
06.03.24, 17:32

The answer is very effective and helpful.

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