Question

Barbara is dragging a 24.0 Kg log up a hill. The hill has a 26.0 degree angle with the horizontal. with what force must she pull in order to make the log accelerate at 2.00 m/s towards the top of the hill

Answer 1

We have:

$$ma=F-mg \sin 26$$

$$F=m(a+g \sin 26)$$

$$F=24(2+9.81 \sin 26) =151N.$$