Question

A 200 g mass is suspended at the 100 cm mark of metre-stick.The metre-stick has a massof 100 g. the magnitude of the sum of the moments about the 0 cm mark is ?

Answer 1

The  magnitude of the sum of the moments about the 0 cm mark is

$$m_2 g l_2 -m_1 g l_1= (m_2 l_2 -m_1 l_1)g$$

$$((0.2)(1) -(0.1)(0.5))10=1.5 Nm$$