Question #87517
What is the mass of an object if it experiences a force of 6.57 N overt a time period of 6.65 while it changes velocity by 11.42m/s
1
Expert's answer
2019-04-05T10:24:50-0400

We can find the mass of the object from the definition of the impulse:


J=FΔt=mΔv,J = F \Delta t = m \Delta v,

here, JJ is the impulse, FF is the force acting on the object, Δt\Delta t is the time period during which the force acting on the object, mm is the mass of the object and Δv\Delta v is the change in the velocity.

Then, we get:


m=FΔtΔv=6.57N6.65s11.42ms=3.82kg.m = \dfrac{F \Delta t}{\Delta v} = \dfrac{6.57 N \cdot 6.65 s}{11.42 \dfrac{m}{s}} = 3.82 kg.

Answer:

m=3.82kg.m = 3.82 kg.


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