Question #87494
A car of mass 500kg accelerates from rest at 1m/s². What is the total distance covered in 1 minute?
1
Expert's answer
2019-04-04T09:06:00-0400

We can find the total distance covered in 1 minute from the kinematic equation:


s=v0t+12at2,s = v_0t + \dfrac{1}{2}at^2,

here, ss is the total distance covered in 1 minute, v0=0v_0 = 0 is the initial velocity of the car, aa is the acceleration of the car and tt is time.

Then, we get:


s=v0t+12at2=0ms60s+121ms2(60s)2=1800m.s = v_0t + \dfrac{1}{2}at^2 = 0 \dfrac{m}{s} \cdot 60 s + \dfrac{1}{2} \cdot 1 \dfrac{m}{s^2} \cdot (60 s)^2 = 1800 m.

Answer:

s=1800m.s = 1800 m.


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