Answer to Question #87066 in Mechanics | Relativity for Aniekan

Question

A body vibrating with simple harmonic motion has a frequency of 4hz and an a amplitude of 0.15m.Calculate the maximum values of the acceleration and velocity
The acceleration and velocity at a point 0.09 from the equilibrium position of motion

Answer 1

If x = 0.15sin25.12t m, then velocity v = 0.15*25.12cos25.12t = 3.77cos25.12t m/s and acceleration a = -94.7sin25.12t m/s². When x = 0.09 m sinωt = 0.6 therefore a₁ = -56.82 m/s² and velocity v₁ = 3.77*0.8 = 3.02 m/s.

So, v_m = 3.77 m/s, v₁ = 3.02 m/s, a_m = 94.7 m/s², a₁ = -56.82 m/s².