Moment of inertia is
"I= 0.5Mr\u00b2 + 4mr\u00b2 = (0.5(4200) + 4(250))(4)^2 =49600 kg\u00b7m^2" The angular acceleration:
"\\alpha=\\frac{\\omega}{t}=\\frac{2\\pi 49}{3600(2.5}=0.034 rad\/s^2" The torque is
"\\tau=I\\alpha=4rF"
"(49600)(0.034)=4(4)F"
"F=110 N"
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