Given:
"l=1.5~\\text{m};~a =0.05~\\text{m};~F=500~\\text{N}. \\\\"
The mechanical advantage:
"MA = \\frac{l-a}{a} = \\frac{F_{resist}}{F}; \\\\" thus:
A)
"MA = \\frac{1.5-0.05}{0.05} = 29.\\\\"
B)
"F_{resist} = F\\frac{l-a}{a} = 500~\\text{N}*\\frac{1.5-0.05}{0.05} = 14500~\\text{N}. \\\\"
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