According to the law of conservation of momentum:
u=(mv1+mv2)/(m+m)=(v1+v2)/2=10m/s Direction of the velocity of the combined mass:
α=135 ̊ The kinetic energy after the collision:
Wk=((m1+m2)u2)/2=100m Fraction of kinetic energy was lost:
ΔT=Wkbeforecollision−Wkaftercollision=(m1m2)(v1−v2)2/2(m1+m2)=0
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