Answer to Question #86586 in Mechanics | Relativity for jagvir dhatt

Question

A 3000-Kg is hoisted 2 m above the ground. Calculate its potential energy

Answer 1

We can find the potential energy from the formula:

$$PE = mgh = 3000 kg \cdot 9.8 \dfrac{m}{s^2} \cdot 2 m = 5.88 \cdot 10^4 J.$$

Answer:

$PE = 5.88 \cdot 10^4 J.$