Question

A horizontal force of 60N acts on a stationary snooker ball of mass 0.2kg.The cue is in contact with the ball for 8/s(0.008s).Calculate the speed of the ball after impact.

Answer 1

A horizontal force of 60N acts on a stationary snooker ball of mass 0.2kg. The cue is in contact with the ball for 8/s(0.008s). Calculate the speed of the ball after impact.

Using second Newton's law:

$$F \Delta t = \Delta p = m v$$

Where $F$ – applied force, $\Delta t$ – contact time, $\Delta p$ – momentum’s change.

$$v = \frac{F \Delta t}{m}$$ $$v = \frac{60N \cdot 0.008s}{0.2kg} = 2.4 \, \text{m/s}$$

Answer: $v = 2.4 \, \text{m/s}$