Answer to Question #86267 in Mechanics | Relativity for Imran Farid

Question #86267
If a pendulum is suspended from a car moving along a plane of angle δ with horizon and car moves with acceleration a, then what is the time period for that pendulum?
1
Expert's answer
2019-03-14T17:45:54-0400
T=2πLwT=2\pi \sqrt{\dfrac{L}{w}}

w=a+g,  w=a2cos2δ+g2\vec{w}=\vec{a}+\vec{g}, \,\, w=\sqrt{a^2\cos^2 \delta +g^2}

T=2πLa2cos2δ+g2T=2\pi \sqrt{\dfrac{L}{\sqrt{a^2\cos^2 \delta +g^2}}}

LL is lenth of pendulum, ww is resulting acceleration, g=9.8g=9.8, TT is time period.


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