Question

If a pendulum is suspended from a car moving along a plane of angle δ with horizon and car moves with acceleration a, then what is the time period for that pendulum?

Answer 1

$$T=2\pi \sqrt{\dfrac{L}{w}}$$

$$\vec{w}=\vec{a}+\vec{g}, \,\, w=\sqrt{a^2\cos^2 \delta +g^2}$$

$$T=2\pi \sqrt{\dfrac{L}{\sqrt{a^2\cos^2 \delta +g^2}}}$$

$L$ is lenth of pendulum, $w$ is resulting acceleration, $g=9.8$, $T$ is time period.