Question

A ball of mass 0.5 kg collides with a wall at a speed of 15.0 ms−1 and bounces back with a speed of 12.5 ms−1. If the average force exerted by the ball is 1100 N calculate the impulse and the time for which the collision lasted.

Answer 1

Answer to Question #85689, Physics / Mechanics | Relativity

Impulse is defined as force applied to a particle for a certain period of time.

$$I = F \Delta t$$ $$I = \Delta P = m \Delta v$$ $$I = 0.50 \times (-12.5 - 15)$$ $$I = 0.50 \times (-12.5 - 15)$$

**I=-13.75 kgm/sec**

Negative sign shows that force on the wall is opposite to force on the ball

Again

$$I = F \Delta t$$

Thus time=I/F=13.75/1100=0.0125 second

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