Answer to Question #84912 in Mechanics | Relativity for Heaven

Question

if a 55 n force is required to move an object that weighs 93 n across a level surface at a constant speed, what is the coefficient of kinetic friction

Answer 1

By the definition of the coefficient of kinetic friction we have:

$\mu_k = \frac{F_{appl}}{W},$

here,

$F_{appl}$

is the horizontal pushing force that required to move an object across a level surface at a constant speed,

$W$

is the weight of the object directed downward.

Then, we get:

$\mu_k = \frac{F_{appl}}{W} = \frac{55 N}{93 N} = 0.59.$

Answer:

$\mu_k = 0.59$

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