Answer to Question #84854 in Mechanics | Relativity for x

Question

A bacterium moves with a speed of 1.6 µm/s across a petri dish with radius
r = 9.1 cm.
How long does it take the bacterium to traverse the petri dish along its diameter?

Answer 1

We can find the time that the bacterium takes to traverse the petri dish along its diameter from the formula:

$$t = \frac{d}{v} = \frac{2r}{v},$$

here,

$$d = 2r$$

is the diameter of the petri dish,

$$r$$

is the radius of the petri dish,

$$v$$

is the speed of the bacterium.

Then, we get:

$$t = \frac{2r}{v} = \frac{2 \cdot 9.1 cm \cdot \frac{1 m}{100 cm}}{1.6 \frac{\mu m}{s} \cdot \frac{1m}{10^6 \mu m}} = 1.14 \cdot 10^5 s.$$

Answer:

$$t = 1.14 \cdot 10^5 s$$

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