Question #84622

An airplane flies 20km in a direction 60 degree north of east then 30 km straight east and then 16km straight north .How far and what direction is the plane from the stating point?

Expert's answer

Answer on question #84622, Physics / Mechanics | Relativity

An airplane flies 20km20\mathrm{km} in a direction 60 degree north of east then 30km30\mathrm{km} straight east and then 16km16\mathrm{km} straight north. How far and what direction is the plane from the stating point?

Solution

x20=cos60x=200.5=10\frac {x}{2 0} = \cos 6 0 {}^ {\circ} x = 2 0 \cdot 0. 5 = 1 0y20=sin60ny=3220=17.32\frac {y}{2 0} = \sin 6 0 {}^ {\circ} n y = \frac {\sqrt {3}}{2} \cdot 2 0 = 1 7. 3 2z=(x+30)2+(16+y)2=52.06z = \sqrt {(x + 3 0) ^ {2} + (1 6 + y) ^ {2}} = 5 2. 0 6cosα=x+30z=4052.06=0.768\cos \alpha = \frac {x + 3 0}{z} = \frac {4 0}{5 2 . 0 6} = 0. 7 6 8α=39.8\alpha = 3 9. 8 {}^ {\circ}


Answer: z=52.06z = 52.06 ; α=39.8\alpha = 39.8{}^{\circ}

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