Answer to Question #83834 in Mechanics | Relativity for Surej

Question

A 2m long fixed string has nodes at both ends when it vibrates in its fundamental
mode. If the distance between this nodes is 25cm. what are the number of (1) nodes
(b) anti-nodes?

Answer 1

Calculate the number of nodes by the relation as follows:

N=L/d+1

Here, L is the length of string and d is the distance between two nodes.

Substitute 2m = 200cm for L and 25 cm for d.

N=(200 cm)/(25 cm)+1

N=9

b. Calculate the number of antinodes by the relation as follows:

A=L/d

Here, L is the length of string and d is the distance between two nodes

Substitute 2m = 200cm for L and 25 cm for d.

A=(200 cm)/(25 cm)

A=8