Answer on Question # 83397, Mechanics/ Relativity
particle moving with uniform acceleration along x axis at x1 = 10 and x2 = 20 at t = 6 and t = 10 respectively. If its velocity at t = 6 is 0.5 m/s it acceleration is
Solution
v2 = v1 + at
v22 = v12 + 2aΔx
Then
(v1 +at)2 = v12 + 2aΔx (1)
where
Δx= x2 - x1 = 20-10= 10 m
Δt = t2 - t1 =10-6 = 4 s
v1 = 0.5 m/s
v2 = 0.5 + a*4
Solve equation (1)for a:
(0.5 + a*4)2 = (0.5)2 + 2a*10
(0.5 + a*4)2 -(0.5)2 = 2a*10
(0.5+4a-0.5)(0.5+4a+0.5) =20a
4a(1+4a)=20a
1+4a =5
a=1 (m/s2)
Answer: a=1 (m/s2)
Comments
Leave a comment