Question #82803
A force F~ = Fx ˆı + Fy ˆ acts on a particle that
undergoes a displacement of ~s = sx ˆı + sy ˆ
where Fx = 8 N, Fy = −2 N, sx = 6 m, and
sy = 3 m.
Find the work done by the force on the
particle.
Answer in units of J.
undergoes a displacement of ~s = sx ˆı + sy ˆ
where Fx = 8 N, Fy = −2 N, sx = 6 m, and
sy = 3 m.
Find the work done by the force on the
particle.
Answer in units of J.
Expert's answer
F=F_x+F_y=8i-2j=8.25e^(-14.04j)
s=s_x+s_y=6i+3j=6.71e^26.57j
A=F·s=8.25e^(-14.04j)·6.71e^26.57j=55.36e^12.53j
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#340153 on Dec 2023
#340153 on Dec 2023
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