For car A:
t_a=t'-t
v_a=u+v
For car B:
t_b=t'
v_b=u
s=(1/2) a_1 (t^'-t)^2=(1/2) a_2 (t^' )^2
Thus,
(1-t/t^' )=(a_2/a_1 )^(1/2)
(u+v)^2=2a_1 s
(u)^2=2a_2 s
So,
(1+v/u)=(a_1/a_2 )^(1/2)
But
u=a_2 t'
So
v/t=(a_1 a_2 )^(1/2)
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