Question #81287

The speed of sound in a medium depends on its wavelength , the young modulus, and the density , of the medium. Use the method of dimensional analysis to derive a formula for the speed of sound in a medium. (Unit for Young Modulus : )
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Expert's answer

2018-09-25T10:34:08-0400

Answer on Question #81287, Physics / Mechanics | Relativity

Question:

The speed of sound in a medium depends on its wavelength, the young modulus, and the density, of the medium. Use the method of dimensional analysis to derive a formula for the speed of sound in a medium. (Unit for Young Modulus : )

Solution:

The dimensional of Young Modulus E\mathrm{E} is Nm2=kgms2m2=kgs2m\frac{N}{m^2} = \frac{\mathrm{kgm}}{s^2m^2} = \frac{\mathrm{kg}}{s^2m} , what means that

(kgs2m)α(kgm3)β(m)γ=ms\left(\frac{kg}{s^2m}\right)^\alpha \left(\frac{kg}{m^3}\right)^\beta (m)^\gamma = \frac{m}{s} i.e. α=0.5=β\alpha = 0.5 = -\beta and γ=0\gamma = 0 , therefore ν=Eρ\nu = \sqrt{\frac{E}{\rho}} , where ρ\rho is the density.

The answer:

The speed of sound in a medium ν=Eρ\nu = \sqrt{\frac{E}{\rho}} , where ρ\rho is the density.

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Comments

Assignment Expert
10.02.20, 16:32

Dear visitor, please use panel for submitting new questions

Laila
09.02.20, 18:40

Could you explain it some more? Why is v=wavelength × density × Young's modulus? And why is it raised to the power of alpha, beta and gamma respectively?

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