Two trains A and B each of length 100m, are moving with their constant speeds.If one train A overtakes the other in 40s and cross the other in 20s. Find speed of each trains.
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Expert's answer
2018-07-24T12:03:09-0400
Let vA and vB be a velocity of two trains A and B. While overtaking the velocity of train A relative to train B is vA - vB m/s. While overtaking or crossing, the trains have to cover a total distance of 100 + 100 = 200 m. Then using the formula Distance = Speed * Time, we can write (vA - vB)*40 = 200 m (1) In case of crossing the velocity of train A relative to train B is vA + vB m/s. The total distance is the same and equal 200 m. Then (vA + vB)*20 = 200 m (2) Let's solve equations 1 and 2. (vA - vB) = 200/40 = 5, (vA + vB) = 200/20 = 10, vA = vB + 5, vB + 5 + vB = 10, 2vB = 5, vB = 5/2 = 2.5 m/s, vA = 2.5 + 5 = 7.5 m/s.
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