Question

A long string of mass per unit length
0.2 kg m-1 is stretched under a tension of
500 N. Calculate the speed of transverse
waves on the string. If this string is joined
to another string of mass per unit length
0.8 kg m-1, calculate the impedances of both
strings.

Answer 1

The speed of transverse waves on the string:
v=√(T/μ)=√(500/0.2)=50 m/s.
The impedances of both strings:
Z_1=√(Tμ_1 )=√((500)(0.2))=10 kg/s.
Z_2=√(Tμ_2 )=√((500)(0.8))=20 kg/s.