Answer to Question #77461 in Mechanics | Relativity for MONIT

Question

In S' a straight rod parallel to the x'axis moves in the y' direction with velocity u. Show that in the S the rod is inclined to the x-axis at an angle -arctan((gamma*u*v)/c^2)

Answer 1

According to relativistic length contraction: l=l_0 √(1-v^2/c^2 ), the rod will contact along y axis:
And so, the angle the rod is inclide to the x-axis is:
tan⁡(φ)=l/l_0 =√(1-v^2/c^2 )
φ=arctan⁡√(1-v^2/c^2 )