Question #74978

The pressure P of an ideal of gas in p is given by the equation P=1/3pC^2) where <C^2> is the mean squared speed and its measured as [speed]^2. Use the base units to show that the equation is homogeneous.

Expert's answer

Answer on Question #74978-Physics-Mechanics-Relativity

The pressure PP of an ideal of gas in pp is given by the equation P=1/3pC∧2P = 1 / 3pC^{\wedge}2 where <C∧2>< C^{\wedge}2 > is the mean squared speed and its measured as [speed] Γ^2\hat{\mathbf{\Gamma}}^2 . Use the base units to show that the equation is homogeneous.

Solution

[P]=Nm2=kgms2m2=kgm−1s−2.[ P ] = \frac {N}{m ^ {2}} = \frac {k g \frac {m}{s ^ {2}}}{m ^ {2}} = k g m ^ {- 1} s ^ {- 2}.[13ρC2]=[13][ρ][C2]=1(kgm3)(m2s2)=kgm−1s−2\left[ \frac {1}{3} \rho C ^ {2} \right] = \left[ \frac {1}{3} \right] [ \rho ] [ C ^ {2} ] = 1 \left(\frac {k g}{m ^ {3}}\right) \left(\frac {m ^ {2}}{s ^ {2}}\right) = k g m ^ {- 1} s ^ {- 2}


Thus,


[P]=[13ρC2][ P ] = \left[ \frac {1}{3} \rho C ^ {2} \right]


So, the equation is homogeneous.

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