Question

Calculate the Coriolis acceleration of an aeroplane flying along the equator due east at
a speed of 300m s−1.

Answer 1

Calculate the Coriolis acceleration of an aeroplane flying along the equator due east at a speed of 300m/s⁻¹. Please explain

Angular speed of the Earth:

$$\omega = 2 \pi f = \frac {6.28}{24 * 3600s} = 7.27 * 10^{-5} s^{-1}$$

Coriolis acceleration:

$$a_{C} = 2[\omega \times v] = 2\omega v$$ $$a_{C} = 2 * 7.27 * 10^{-5} s^{-1} * 300 \, \text{m/s} = 0.044 \, \text{m/s}^2$$

Answer: $a_{C} = 0.044 \, \text{m/s}^2$