Question #74175

A uniform rod AB is of length l and weight 2W. It can turn freely about a smooth hinge at its upper end A. The rod is held in equilibrium by means of a horizontal force P applied at B, which is at a distance a from the vertical line through A. Find the value of P and show that the reaction at the hinge is W [(4l^2-3a^2)/(l^2-a^2)] ^1/2
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Expert's answer

2018-03-06T09:48:07-0500

Answer on Question #74175-Physics-Mechanics-Relativity

A uniform rod AB is of length I and weight 2W. It can turn freely about a smooth hinge at its upper end A. The rod is held in equilibrium by means of a horizontal force P applied at B, which is at a distance a from the vertical line through A. Find the value of P and show that the reaction at the hinge is W [(4I^2-3a^2)/(I^2-a^2)] ^1/2

Solution

P=Tsinα=TalP = T \sin \alpha = T \frac {a}{l}W=Tcosα=T12a2lW = T \cos \alpha = T \frac {\sqrt {1 ^ {2} - a ^ {2}}}{l}


Thus,


P=Wa12a2P = W \frac {a}{\sqrt {1 ^ {2} - a ^ {2}}}


The reaction at the hinge is


T=Wcosα=Wl12a2T = \frac {W}{\cos \alpha} = W \frac {l}{\sqrt {1 ^ {2} - a ^ {2}}}


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