Question #73979

Object thrown up Vi = 110 m/s,
sketch a V vs t plot of the object
from the throw to the peak (use a = -10 m/s2)
1

Expert's answer

2018-02-26T09:10:07-0500

Answer on Question #73979 Physics / Other

Object thrown up vi=110m/sv_i = 110 \, \text{m/s}, sketch a vv vs tt plot of the object from the throw to the peak (use a=10m/s2a = -10 \, \text{m/s}^2).

Solution:

The time dependence of the velocity


v(t)=vi+atv(t) = v_i + a t


In our case


v(t)=11010tv(t) = 110 - 10 t


Object reaches the maximum height within the time


t=via=11010=1.1st = \frac{v_i}{-a} = \frac{110}{10} = 1.1 \, \text{s}


Thus the vv vs tt plot of the object is as follows



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