Question #7385

a laser fires at frequency of 40 hertz.. Using c=3x10 to the 8 meters per second,how far apart is each pules?

Expert's answer

A laser fires at frequency of 40 hertz. Using c=3×10c = 3 \times 10 to the 8 meters per second, how far apart is each pulse?



Distance between two adjacent pulses (look at figure):


d=x+l2+l2=x+ld = x + \frac {l}{2} + \frac {l}{2} = x + l


Total length of the NN pulses:


S=Nd=ctS = N d = c t


where NN number of pulses, cc - speed of light, tt - time.


d=ctN=cNt=cfd = \frac {c t}{N} = \frac {c}{\frac {N}{t}} = \frac {c}{f}d=3108m/s40Hz=7.5106md = \frac {3 * 1 0 ^ {8} m / s}{4 0 H z} = 7. 5 * 1 0 ^ {6} m


Answer: d=7.5106md = 7.5 * 10^{6}m

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