A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider
is 0.870 m/s at an angle of 35.0o
above the table, and it lands on the magazine 0.0770 s after leaving the
table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.
1
Expert's answer
2018-02-21T03:48:08-0500
Inclined distance covered =velocity time 0.870 0.0770= 0.06699m X=thickness of magazine X=0.06699 ( ) =0.033495 33.495mm
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