Question #73271

Wheels on a bicycle have a radius of 0.50 m. If the bicycle is traveling at a speed of 4.0 m/s, what is the period of rotation of its wheels?
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Expert's answer

2018-02-07T15:19:07-0500

Answer on Question 73271, Physics, Mechanics, Relativity

Question:

Wheels on a bicycle have a radius of 0.50m0.50\,m. If the bicycle is traveling at a speed of 4.0m/s4.0\,m/s, what is the period of rotation of its wheels?

Solution:

When the wheel of a bicycle makes one revolution it travels a distance equals to its circumference. Therefore, we can find the period of rotation of bicycle wheels from the formula:


v=CT=2πrT,v = \frac{C}{T} = \frac{2\pi r}{T},


here, v=4.0m/sv = 4.0\,m/s is the speed of the bicycle, C=2πrC = 2\pi r is the circumference of the bicycle wheel, r=0.50mr = 0.50\,m is the radius of the bicycle wheel and TT is the period of rotation of bicycle wheels.

Then, we get:


T=2πrv=2π0.50m4ms=0.785s.T = \frac{2\pi r}{v} = \frac{2 \cdot \pi \cdot 0.50\,m}{4\, \frac{m}{s}} = 0.785\,s.


Answer:

T=0.785sT = 0.785\,s

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