Answer on Question #73127- Physics / Mechanics | Relativity
A student is pushing a m=35 kg desk across a floor at a constant speed of v1=4m/s. How much work, to the nearest whole joule, must the student do on the desk to change the speed to v2=6m/s?
Solution:
Work done = change of energy
W=2mv22−2mv12W=235×36−235×16=630−280=350J
Answer W=350J
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