Question #73127

A student is pushing a 35 kg desk across a floor at a constant speed of 4 m/s. How much work, to the nearest whole joule, must the student do on the desk to change the speed to 6 m/s?
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Expert's answer

2018-02-02T08:46:07-0500

Answer on Question #73127- Physics / Mechanics | Relativity

A student is pushing a m=35m = 35 kg desk across a floor at a constant speed of v1=4m/sv_{1} = 4 \, \text{m/s}. How much work, to the nearest whole joule, must the student do on the desk to change the speed to v2=6m/sv_{2} = 6 \, \text{m/s}?

Solution:

Work done = change of energy


W=mv222mv122W = \frac{m v_{2}^{2}}{2} - \frac{m v_{1}^{2}}{2}W=35×36235×162=630280=350JW = \frac{35 \times 36}{2} - \frac{35 \times 16}{2} = 630 - 280 = 350 \, \text{J}


Answer W=350JW = 350 \, \text{J}

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