An object of density 20 grams per centimetre cube weighs 200 grams when suspended from a spring balance. It is then inserted into a liquid of density 0.6 grams per cm cube until 1/3 of its volume is immersed in the liquid. Calculate the tension in the spring in newton.
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Expert's answer
2018-01-26T14:51:08-0500
Density of the object , D = 20 gm / cm cube Mass , M = 200 gram
Therefore, Volume of the object is , V = M/D = 200 / 20 cm cube Volume immersed in the liquid is = V/3
= 10/3 cm cube
Therefore the buoyancy force exerted by the liquid = volume × density × g =( 10/3)× 0.6 × 980 =1960 dyne Tension force will be = weight - buoyancy = Mg - 1960 =( 200× 980 )- 1960 =196000 - 1960 =194040 dyne or 1.94 N
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