Question #72843

A horizontal rod with a mass of 10 kg and length 12 m is hinged to a wall at one end
and supported by a cable which makes an angle of 30º with the rod at its other end.
Calculate the tension in the cable and the force exerted by the hinge.
1

Expert's answer

2018-01-29T10:21:07-0500

Question #72843, Physics / Mechanics | Relativity

A horizontal rod with a mass of 10kg10\mathrm{kg} and length 12m12\mathrm{m} is hinged to a wall at one end and supported by a cable, which makes an angle of 3030{}^{\circ} with the rod at its other end. Calculate the tension in the cable and the force exerted by the hinge.

Solution



The net moment around the hinge is zero.


M=0;10×122×g+Tsin30×10=0;T=60g10×sin30=12g=117.72NFx=0;Rx=Tcos60;Rx=117.72×cos60=58.86NFy=0;Ry+Tsin30=mg;Ry=mgTsin30;Ry=12×9.81117.72×sin30=58.86NR=Rx2+Ry2=2×58.862=83.24N\begin{array}{l} \sum M = 0; \\ - 1 0 \times \frac {1 2}{2} \times g + T \sin 3 0 {}^ {\circ} \times 1 0 = 0; \\ T = \frac {6 0 g}{1 0 \times \sin 3 0 {}^ {\circ}} = 1 2 g = 1 1 7. 7 2 \mathrm {N} \\ \sum F _ {x} = 0; \\ R _ {x} = T \cos 6 0 {}^ {\circ}; \\ R _ {x} = 1 1 7. 7 2 \times \cos 6 0 {}^ {\circ} = 5 8. 8 6 \mathrm {N} \\ \sum F _ {y} = 0; \\ R _ {y} + T \sin 3 0 {}^ {\circ} = m g; \\ R _ {y} = m g - T \sin 3 0 {}^ {\circ}; \\ R _ {y} = 1 2 \times 9. 8 1 - 1 1 7. 7 2 \times \sin 3 0 {}^ {\circ} = 5 8. 8 6 \mathrm {N} \\ R = \sqrt {R _ {x} ^ {2} + R _ {y} ^ {2}} = \sqrt {2 \times 5 8 . 8 6 ^ {2}} = 8 3. 2 4 \mathrm {N} \\ \end{array}


Answer: tension 117.72 N, the force exerted by the hinge 83.24 N.

Answer provided by https://www.AssignmentExpert.com

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS