Question #72538

Water flows out of a pipe at the rate of 3.0 cm^3/s. Determine the velocity of the H2O at a point where its diameter is a) 0.50 cm & b) 0.80 cm
1

Expert's answer

2018-01-17T06:20:56-0500

Answer on Question #72538-Physics-Mechanics-Relativity

Water flows out of a pipe at the rate of 3.0 cm3/s3.0~\mathrm{cm}^3/\mathrm{s}. Determine the velocity of the H2O at a point where its diameter is a) 0.50 cm0.50~\mathrm{cm} & b) 0.80 cm0.80~\mathrm{cm}

Solution

dVdt=Av.\frac {d V}{d t} = A v.A=πd24.A = \frac {\pi d ^ {2}}{4}.


Thus,


dVdt=πd24v\frac {d V}{d t} = \frac {\pi d ^ {2}}{4} v


a)


v=4π3.0(0.50)2=15cms.v = \frac {4}{\pi} \frac {3.0}{(0.50)^2} = 15 \frac {cm}{s}.


b)


v=4π3.0(0.80)2=6.0cms.v = \frac {4}{\pi} \frac {3.0}{(0.80)^2} = 6.0 \frac {cm}{s}.


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