A shopper in a supermarket pushes a cart
with a force of 38 N directed at an angle of
26.4◦ downward from the horizontal.
Find the work done by the shopper as she
moves down a 49.2 m length of aisle.
Answer in units of kJ.
As you know work is the force multiplies the distance.
In this case we need consider only the horizontal component of force
Fh=F*sin α=38*sin 26.4=16.9
because there no any moving in vertical plane.
Then the work is A=Fh*l=16.9*49.2=831J=0.83kJ
Answer 0.83kJ
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