a)
distance between them d2=d^2 =d2= (bo cos theoreme)
=23∧2+14∧2−2∗14∗23∗cos60=403= 23^{\wedge}2 + 14^{\wedge}2 - 2^{*}14^{*}23^{*}\cos 60 = 403=23∧2+14∧2−2∗14∗23∗cos60=403
So d=20d = 20d=20
b)
by sin theorem
20/sin60=14/sina, where a is
Sina=0.7*sin60
Sina=0.6
a=arcsin0.6
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