Question

Jane swims the length of a 40 meter pool in 10 seconds and immediately swims back to the starting position in another 15 seconds. What was her average velocity?

Answer 1

Answer on Question 71569, Physics, Mechanics, Relativity

Question:

Jane swims the length of a 40 meter pool in 10 seconds and immediately swims back to the starting position in another 15 seconds. What was her average velocity?

Solution:

The average velocity of an object is defined as the displacement per unit time:

$$v_{avg} = \frac{\text{displacement}}{\text{time taken}}.$$

Because Jane returns to the starting position, the displacement is equal to zero and we get:

$$v_{avg} = \frac{\text{displacement}}{\text{time taken}} = \frac{0\ \text{m}}{25\ \text{s}} = 0\ \frac{\text{m}}{\text{s}}.$$

Answer:

$$v_{avg} = 0\ \text{m/s}.$$

Answer provided by https://www.AssignmentExpert.com