a taxi driver allows his taxi cab weighing 17.08 kN to coast in neutral, and air resistance decelerates the car from 35.8 m/s to 22.4 m/s in a period of 24 seconds. calculate (a) the average deceleration, (b) the displacement of the car while it is decelerating.
1
Expert's answer
2012-03-01T10:25:04-0500
(a) the average deceleration
Let a be the average deceleration. Then V(t) = at + V0. We know that V(T) = V1, so aT + V0 = V1, or 24a + 35.8 = 22.4 ==> a = (22.4-35.8)/24 = -67/120 m/s².
(b) the displacement of the car while it is decelerating.
We'll use the formula D(t) = at²/2 + V0*t. So, D(T) = aT²/2 + V0*T = -67/120*24²/2 + 35.8*24 = 3492/5 m.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment