Question #68035

Two weights connected by a lightweight string running over a pully is known as an Atwoods Machine. Determine the acceleration of the two masses of a simple Atwood’s machine, with one fixed pulley and two masses m1 and m2. (m1 > m2)
(Do free-body diagram first for each weight.)
1

Expert's answer

2017-05-05T13:07:09-0400

Answer on Question #68035-Physics-Mechanics | Relativity

Two weights connected by a lightweight string running over a pully is known as an Atwoods Machine. Determine the acceleration of the two masses of a simple Atwood's machine, with one fixed pulley and two masses m1 and m2. (m1 > m2)

(Do free-body diagram first for each weight.)

Solution

A free-body diagram for first weight:



A free-body diagram for second weight:


{m1a=m1gTm2a=Tm2g\left\{ \begin{array}{l} m _ {1} a = m _ {1} g - T \\ m _ {2} a = T - m _ {2} g \end{array} \right.(m1+m2)a=(m1m2)g(m _ {1} + m _ {2}) a = (m _ {1} - m _ {2}) g


The acceleration of the two masses of a simple Atwood's machine is


a=(m1m2)(m1+m2)g=1m2m11+m2m1ga = \frac {(m _ {1} - m _ {2})}{(m _ {1} + m _ {2})} g = \frac {1 - \frac {m _ {2}}{m _ {1}}}{1 + \frac {m _ {2}}{m _ {1}}} g


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