Answer Question #67081, Physics / Mechanics | Relativity
A 100 cm long string vibrates in 4 loops at 50 Hz. Linear density of the string is 0.0004 gm/cm. Calculate the tension in the string.
Find: T – ?
Given:
L = 1 m L = 1 \text{ m} L = 1 m f = 50 Hz f = 50 \text{ Hz} f = 50 Hz μ = 0.0004 gm cm 3 = 0.0004 × 1 0 − 3 kg cm 3 = 0.4 kg m 3 \mu = 0.0004 \frac{\text{gm}}{\text{cm}^3} = 0.0004 \times \frac{10^{-3} \text{ kg}}{\text{cm}^3} = 0.4 \frac{\text{kg}}{\text{m}^3} μ = 0.0004 cm 3 gm = 0.0004 × cm 3 1 0 − 3 kg = 0.4 m 3 kg n = 4 n = 4 n = 4
Solution:
f = n 2 L T μ ( 1 ) f = \frac{n}{2L} \sqrt{\frac{T}{\mu}} \quad (1) f = 2 L n μ T ( 1 ) Of ( 1 ) ⇒ T = f 2 4 L 2 μ n 2 ( 2 ) \text{Of } (1) \Rightarrow T = \frac{f^2 4L^2 \mu}{n^2} \quad (2) Of ( 1 ) ⇒ T = n 2 f 2 4 L 2 μ ( 2 ) Of ( 2 ) ⇒ T = 250 N \text{Of } (2) \Rightarrow T = 250 \text{ N} Of ( 2 ) ⇒ T = 250 N
Answer:
250 N
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