Question

A car traveling at 30 m/s overcomes a frictional resistance of 100N while moving. Calculate the power developed by the engine. [1 hp = 0.75Kw
(a) 0.23hp (b) 0.40hp (c) 4.00hp (d) 4.40hp

Answer 1

Answer on Question #67042- Physics / Mechanics - Relativity

A car traveling at $30\,\mathrm{m/s}$ overcomes a frictional resistance of 100N while moving. Calculate the power developed by the engine. $[1\,\mathrm{hp} = 0.75\,\mathrm{Kw}]$ (a) 0.23hp (b) 0.40hp (c) 4.00hp (d) 4.40hp

Solution

The power developed by the engine

$$\begin{aligned} P &= \frac{\text{work done}}{\text{time}} \\ &= \frac{A}{t} = \frac{Fs}{t} = Fv \\ &= 100\,\mathrm{N} \times 30\,\frac{\mathrm{m}}{\mathrm{s}} = 3000\,\mathrm{W} = 4.00\,\mathrm{hp} \end{aligned}$$

**Answer:** (c) $P = 4.00\,\mathrm{hp}$

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