Question #6681

a box of mass 50kg is pulled up from the hold of a ship with an acceleration of 1m/s2 by a vertical rope attached to it.Find the tension in the rope what is the tension in the rope when the box moves up with a uniform velocity of 1m/s

Expert's answer

A box of mass 50kg is pulled up from the hold of a ship with an acceleration of 1m/s2 by a vertical rope attached to it. Find the tension in the rope what is the tension in the rope when the box moves up with a uniform velocity of 1m/s.

Second Newton's law:


TFg=MaT - F _ {g} = M aT=Fg+Ma=Mg+Ma=M(g+a)T = F _ {g} + M a = M g + M a = M (g + a)T=50kg(9.8m/s2+1m/s2)=540NT = 50kg * (9.8m/s^2 + 1m/s^2) = 540N


If the box moves with uniform velocity, the rope tension is equal to the box's weight at rest:


T=Mg=50kg9.8m/s2=490NT = Mg = 50kg * 9.8m/s^2 = 490N

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